Modulus Question
AppId is over the quota
AppId is over the quota
The function f is defined for all real values of x by
AppId is over the quota
The function f is defined for all real values of x by
The diagram shows this (it shows you intersections).
Find the set values of x for which ![]()
Well, the root of the equation is
and on the left side of this (you can see on the graph), all of the f(x) values are positive. On the right they're all negative. So it's clear for f(x) = |f(x)| that it'll be on the left of the root.
But my question is... Is the set of x values
or is it ![]()
Technically when
, f(x) = |f(x)|... 0 = |0|... But yeah, I always get confused about little things like this.

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