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C3-help - algebraic fractions

20:15 Publicado por Mario Galarza

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Discussion, revision, testing and homework help mathematics and statistics.

12 Minutes ago: 5 September 2011 15: 47

can someone help? This is the question:

Simplify:

$\frac{3x+1}{(x+2)^3} - \frac{2}{(x+2)^2} + \frac{4}{(x+2)}$

This is what I did:

$\frac{3x+1}{(x+2)^3} - (\frac{2}{(x+2)^2} + \frac{4}{(x+2)})$

$= \frac{3x+1}{(x+2)^3} - \frac{2 + 4(x+2)}{(x+2)^2}$

$= \frac{3x+1 - (x+2)[2+4(x+2)]}{(x+2)^3}$

$= \frac{3x+1 - [2(x+2)+4(x+2)^2]}{(x+2)^3}$

$= \frac{3x+1 - 2 - 4(x+2)^2}{(x+2)^2}$

$= \frac{3x+1-2-4x^2-16x-16}{(x+2)^2}$

$= \frac{-4x^2-13x-17}{(x+2)^2}$

The correct answer is $\frac{4x^2+17x+13}{(x+2)^2}$

I don't know what I'm doing, wrong advice welcome.

8 Minutes ago: 5 September 2011 15: 51 Re: C3 help - algebraic fractions

can someone help? This is the question:

Simplify:

$\frac{3x+1}{(x+2)^3} - \frac{2}{(x+2)^2} + \frac{4}{(x+2)}$

This is what I did:

$\frac{3x+1}{(x+2)^3} - (\frac{2}{(x+2)^2} + \frac{4}{(x+2)})$

These two statements are not equivalent.

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Etiquetas: algebraic, C3help, fractions

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